Det Oväntade Med Att Komma Igång Med RCS I Mobilen
In any case, because of this fact, we must have that det(AB) = cdet(B) det (A B) = c det (B) for some constant c c, and setting B = I B = I, we see that c= det(A) c = det (A). For completeness, here is a. A matrix A A is hermitian if and only if its conjugate transpose A∗ A ∗ is the same as A A. In this case, obviously, det(A) = det(A∗) det (A) = det (A ∗), but this is not generally true. You can decompose.
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