Aggregator Services Streamline Your Data From Multiple Sources Fast
Aggregator - GroupBy In an aggregator, if you do NOT have 'Sorted Input' selected and input to the aggregator is not sorted, will the output from the aggregator be ordered (sorted) by the 'GroupBy' ports? Hi Prasanna, I think in this scenario we should use sorted to get distinct records.Because to get distinct data from aggregator we need to select all ports as a groupby. So aggregrator will take some time. Hi , In the Informatica documentation for the aggregator I see the following : When selecting multiple group by ports in the Aggregator transformation, the Integration Service uses port order to determine. This can be achieved in the following three steps :- 1) Expression transformation :- use a iff condition to define the columns with the particular string and where err_cd=0 2) Aggregator :-Then use the. Hi All, I am using Aggregator transformation in my mapping. Example details: Name Serial No Address Hari 1111 47, New street Hari 1111 Bangalore Hari 1111 Karnataka Suresh 2222 50 Old Street Suresh.
Will using an aggregator transformation and using Group By Order & using expression in aggregator as MAX (Version) work in this case? I know it will return only the row where Version is 2 but will it. Prad.Kann 10 years ago I found using the last function along with aggregator and joiner helps to identify the last record. I created two source definition reading from the same file. The first source reads all. > We can use ' Distinct ' property in Sorter Transformation to eliminate records from flat file or relational sources, but we can't use source qualifier SQL override for flat files. > But If you select the Disctinct. D, 1 Now pass the output of expression transformation, aggregator transformation to joiner transformation and join on the products port. In the joiner transformation check the property sorted.
Data Aggregation & Analysis for Enhanced Wealth Management
